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The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is v. The velocity of an electron in its fifth orbit will be |
v $\frac{22}{5}$ v $\frac{5}{2}$ v $\frac{2}{5}$ v |
$\frac{2}{5}$ v |
$v_n \propto \frac{1}{n} \Rightarrow \frac{v_5}{v_2}=\frac{2}{5} \Rightarrow v_5=\frac{2}{5} v_2=\frac{2}{5} v$ |
