The length of each side of a rhombus is 10 cm. If the length of one of its diagonals is 16 cm, then what is the area of the rhombus?

96 cm²

Given = The length of each side of a rhombus =10 cm.

The length of one of its diagonals = 16 cm

We know that,

CB² = OB² + OC²

10² = 8² + OC²

100 = 64 + OC² 

OC² = 100 - 64 = 36

OC = \(\sqrt {36}\)   = 6

Then diagonal AC = 6 × 2 = 12

We know that the area of the rhombus = \(\frac{1}{2}\) × D1× D2

= \(\frac{1}{2}\) × 12 × 16 = 96cm²