Present ages of A and B are in the ratio of 13 : 7 . If the present age of C is 39 years and A's present age is \(\frac{4}{3}\) of C's present age, then after how many years the ages of A and B would be in the ratio of 5 : 3 ?
Answer & explanation
Correct answer: option 1
C = 39 years
A = 39 × \(\frac{4}{3}\) = 52 years
Ratio of present age of A and B = 13x : 7x
⇒ 13x = 52 ⇒ x = 4
Hence, B'age ⇒ 7x = 28 years
ATQ, let time is t years:
⇒ \(\frac{52\;+\;t}{28\;+\;t}\) = \(\frac{5}{3}\)
⇒ 156 + 3t = 140 + 5t
⇒ 2t = 16
⇒ t = 8