Practicing Success
Practicing Success
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If A = \(\begin{bmatrix}13 & 5\\3 & 1 \end{bmatrix}\), then what can be said about 8\( { A }^{ -1 } \)? |
8\( { A }^{ -1 } \) = 4 (adj A) 8\( { A }^{ -1 } \) = -4 (adj A) 8\( { A }^{ -1 } \) = 2 (adj A) 8\( { A }^{ -1 } \) = -2(adj A) |
8\( { A }^{ -1 } \) = -4 (adj A) |
\( { A }^{ -1 } \) =\(\frac{adj A}{|A|}\) But |A| = -2 So, \( { A }^{ -1 } \) =\(\frac{adj A}{-2}\) 8 \( { A }^{ -1 } \) = 8 \(\frac{adj A}{-2}\) =- 4 (adj A) |
