Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

In the nth orbit, the energy of an electron $E_n=-\frac{13.6}{n^2} eV$ for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be

Options:

10.2 eV

12.1 eV

13.6 eV

3.4 eV

Correct Answer:

10.2 eV

Explanation:

Given, $E_n=-\frac{13.6}{n^2} eV$ 

$E_{1 \rightarrow 2}=-3.4-(13.6)=+10.2 eV$