In the nth orbit, the energy of an electron $E_n=-\frac{13.6}{n^2} eV$ for hydrogen atom. The energy required to take the electron from first orbit to second orbit will be
Answer & explanation
Correct answer: option 1
Given, $E_n=-\frac{13.6}{n^2} eV$
$E_{1 \rightarrow 2}=-3.4-(13.6)=+10.2 eV$