If \(\frac{a}{b}\) + \(\frac{b}{a}\) = 2 Find \(\frac{a\;+\;b}{ab}\).

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2

Formula → x + \(\frac{1}{x}\) = 2, then x = 1 always Put \(\frac{a}{b}\) = 1 \(\frac{b}{a}\) = 1 \(\frac{a\;+\;b}{ab}\) = 2