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CUET
General Test
Quantitative Reasoning
Algebra
If \(\frac{a}{b}\) + \(\frac{b}{a}\) = 2
Find \(\frac{a\;+\;b}{ab}\).
0
2
1
3
Formula → x + \(\frac{1}{x}\) = 2, then x = 1 always
Put \(\frac{a}{b}\) = 1
\(\frac{b}{a}\) = 1
\(\frac{a\;+\;b}{ab}\) = 2