If A and B are two events such that P(A) = 1/4 and P(B) = 1/2 and P(A∩B) = 1/8, find P(not A and not B)-
Answer & explanation
Correct answer: option 2
It is given that P(A) = 1/4 and P(B) = 1/2 and P(A∩B) = 1/8
P(not on A and not on B) = P(A′∩B′)
= P((A∪B))′
= 1- P(A∪B)
= 1 - {P(A) + P(B) - P(A∩B)}
= 1- { (1/4) + (1/2) - (1/8) }
P(not on A and not on B)= 3/8
P(not on A and not on B)
P(not on A and not on B)