A DC motor is rated at 20 A with a voltage of 115 V. When the motor is running at its maximum power, it can lift an object with a weight of 4900.00 N a distance of 10.00 m, in 30.00 s, at a constant speed.
What is the power used in lifting the object? Ignore air resistance.
Answer & explanation
Correct answer: option 1
P = FS/t
F : 4900 N ; S = 10 m ; t = 30 s
P = 4900/3 = 1633.33 W