Match List I with List II
| List I | List II |
| (A) \([Co(NH_3)_5SO_4]Br\) | (I) Coordination isomerism |
| (B) \([Co(NH_3)_5(NO_2)]Cl_2\) | (II) Geometrical isomerism |
| (C) \([Co(NH_3)_6][Cr(CN)_6]\) | (III) Linkage isomerism |
| (D) \([CoCl_2(en)_2]\) | (IV) Ionization isomerism |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → A-IV, B-III, C-I, D-II
(A) [Co(NH3)5SO4]Br — This matches (IV) Ionization isomerism. The counter ion \( \ce{Br-} \) can change place with the \( \ce{SO4^2-} \) ligand, giving \( \ce{[Co(NH3)5Br]SO4} \); the two give different ions in solution.
(B) [Co(NH3)5(NO2)]Cl2 — This matches (III) Linkage isomerism. \( \ce{NO2-} \) is ambidentate; it can bind through N (nitro) or through O (nitrito, –ONO).
(C) [Co(NH3)6][Cr(CN)6] — This matches (I) Coordination isomerism. Both ions are complexes, and the ligands can be exchanged between the two metals: \( \ce{[Cr(NH3)6][Co(CN)6]} \).
(D) [CoCl2(en)2] — This matches (II) Geometrical isomerism. An octahedral [MX2(L–L)2] complex has cis and trans forms.