Practicing Success
Practicing Success
CUET Preparation Today
| If \(\vec{a}\) and \(\vec{b}\) are two vectors, then angle between vectors \(\vec{a}+\vec{b}\) and \(\vec{a}\times \vec{b}\) is |
\(0^{\circ}\) \(60^{\circ}\) \(90^{\circ}\) \(120^{\circ}\) |
| \(90^{\circ}\) |
| \(\cos \theta=\frac{(\vec{a}+\vec{b})\cdot (\vec{a}\times \vec{b})}{|\vec{a}+\vec{b}||\vec{a}\times \vec{b}|}\)=0, so option (c) is correct |
