The value of the integral $∫\left(e^x tan^{-1}x+\frac{e^x}{1+x^2}\right) dx $ is :

$e^x\, tan^{-1} x + C, $ where C is a constant $e^x\, tan x + C, $ where C is a constant $e^{-x}\, tan x + C, $ where C is a constant $e^{-x}\, tan^{-1} x + C, $ where C is a constant

$e^x\, tan^{-1} x + C, $ where C is a constant