If tan θ $=\frac{20}{21},$ then the value of $\frac{sinθ-cosθ}{sinθ+cosθ}$ is :
Answer & explanation
Correct answer: option 1
tan θ = \(\frac{20}{21}\)
{ tan θ = \(\frac{P}{B}\) }
Now,
\(\frac{sinθ - cosθ}{sinθ + cosθ}\)
= \(\frac{P - B}{P + B}\)
= \(\frac{20 - 21}{20 + 21}\)
= \(\frac{-1}{41}\)