A man loses 12\(\frac{1}{2}\)% of his money and after spending 70% of the remainder, he is left with Rs. 210. How much money had he at first?
Answer & explanation
Correct answer: option 4
We know that 12\(\frac{1}{2}\)% = \(\frac{1}{8}\)
& 70% = \(\frac{7}{10}\)
If loses 12\(\frac{1}{2}\)% then remaining = \(\frac{7}{8}\)
If spending 70% then remaining = \(\frac{3}{10}\)
Let initial amount = Rs. x
ATQ,
x × \(\frac{7}{8}\) × \(\frac{3}{10}\) = 210
x = 800