CUET Preparation Today
The average electric field of electromagnetic waves in certain region of free space is $9 × 10^{–4} NC^{–1}$. Then the average magnetic field in the same region is |
$27×10^{-4}T$ $3×10^{-12}T$ $\left(\frac{1}{3}\right)×10^{-12}T$ $3×10^{12}T$ |
$3×10^{-12}T$ |
The correct answer is option (2) : $3×10^{-12}T$ $C=\frac{E_{avg}}{B_{avg}}$ $⇒B_{avg}=\frac{9×10^{-4}}{3×10^{8}}=3×10^{-12}T$ |
