Two identical containers A and B having same volume of an ideal gas at the same temperature have mass of the gas as m_A and m_B respectively, 2m_A = 3 m_B. The gas in each cylinder expand isothermally to double its volume. If the change in pressure in A is \(\Delta p\), find the change in pressure in B : 

(4/3) \(\Delta p\)

2 m_A = 3 m_B

\(p_A V = \frac{m_A}{M}RT\)

\(p_B V = \frac{m_A}{m}RT = \frac{2m_A}{3 M}RT\)

So, \(\frac{p_A}{p_B} = \frac{3}{2}\)

The expansion is isothermal, so pressure will reduce to half when volume is doubled.

\(p_A - \frac{p_A}{2} = \Delta p\)

\(\Rightarrow p_A = 2 \Delta p\)

\(p_B - \frac{p_B}{2} = \frac{p_B}{2}\)

\(p_B - \frac{p_B}{2} = \frac{1}{2} \frac{2}{3} p_A\)

\(p_B - \frac{p_B}{2} = \frac{1}{3} p_A = \frac{2}{3} \Delta p\)

\(p_B = \frac{4}{3} \Delta p\)