The speed of two railway engines is in the ratio 5 : 4. If they move on parallel tracks in the same direction and if the slower engine is ahead of the faster engine by 8 km when the latter starts, then how far will the faster engine have to travel before it overtakes the slower one?

40

According to question ,

Speed ratio of two engines is = 5 : 4

Let the speed of the faster engine = 5 km/hr

and speed of the slower engines is 4 km/hr

The distance between the two engines = 8 km

Required time to overtake by faster engine = \(\frac{8}{(5-4)}\) = 8 hr

Distance covered by the faster engine in 8 hrs = 5 × 8 = 40 km