What is the value of cos($-\frac{17π}{3}$)?
Answer & explanation
Correct answer: option 3
cos($-\frac{17π}{3}$) = cos($-6π + \frac{π}{3}$)
= cos($6π - \frac{π}{3}$)
(because cos(-A) = cosA)
= cos($\frac{π}{3}$) = $\frac{1}{2}$
What is the value of cos($-\frac{17π}{3}$)?
Correct answer: option 3
cos($-\frac{17π}{3}$) = cos($-6π + \frac{π}{3}$)
= cos($6π - \frac{π}{3}$)
(because cos(-A) = cosA)
= cos($\frac{π}{3}$) = $\frac{1}{2}$