Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

What is the value of cos($-\frac{17π}{3}$)?

Options:

1

$\frac{\sqrt{3}}{2}$

$\frac{1}{2}$

0

Correct Answer:

$\frac{1}{2}$

Explanation:

cos($-\frac{17π}{3}$) = cos($-6π + \frac{π}{3}$)

                              = cos($6π - \frac{π}{3}$)

               (because cos(-A) = cosA)

                               = cos($\frac{π}{3}$) = $\frac{1}{2}$