CUET Preparation Today
CUET
-- Mathematics - Section B2
Calculus
If $x=at^2, y -\frac{a}{t^2}, $ then the value of $\frac{d^2y}{dx^2}$ at t =1 is :
$\frac{2}{a}$
$\frac{2}{3a}$
$2a$
$\frac{a}{2}$
