A network of six identical capacitors, each of value C is made as shown in the figure. Equivalent capacitance between points A and B is |
C/4 3C/4 4C/3 3C |
4C/3 |
The network is equivalent to Therefore equivalent capacitance = [2C series C] / [C series 2C] $=2\left(\frac{2 C \times C}{2 C+C}\right)=\frac{4 C}{3}$ |