A network of six identical capacitors, each of value C is made as shown in the figure. Equivalent capacitance between points A and B is
Answer & explanation
Correct answer: option 3
The network is equivalent to
Therefore equivalent capacitance = [2C series C] / [C series 2C]
$=2\left(\frac{2 C \times C}{2 C+C}\right)=\frac{4 C}{3}$