From a pack of 52 cards one card is drawn at random. What is the probability that the card drawn is a ten or a spade? |
$\frac{1}{4}$ $\frac{4}{13}$ $\frac{1}{13}$ $\frac{1}{26}$ |
$\frac{4}{13}$ |
Here n(S) = 52 There are 13 spades (including one ten) and there are 3 more tens Let E = event of getting a ten or a spade Then n(E) = (13+3) = 16 P(E) = n(E)/ n(S) = 16/52 = 4/13 The correct answer is Option (2) → $\frac{4}{13}$ |