From a pack of 52 cards one card is drawn at random. What is the prob…

Here n(S) = 52

There are 13 spades (including one ten) and there are 3 more tens

Let E = event of getting a ten or a spade

Then n(E) = (13+3) = 16

P(E) = n(E)/ n(S) = 16/52 = 4/13

The correct answer is Option (2) → $\frac{4}{13}$