CUET Preparation Today
A current i is flowing in a conductor of length l. When it is bent in the form of a loop then its magnetic moment will be- |
$\frac{Il^2}{4\pi}$ $\frac{I^2}{4\pi}$ $\frac{4\pi}{Il^2}$ $4\pi Il^2$ |
$\frac{Il^2}{4\pi}$ |
$ M = IA = I\pi r^2$ $ 2\pi r = l $ $\Rightarrow M = I \pi \frac{l^2}{4\pi^2} = \frac{Il^2}{4\pi}$ |
