If tan A = 2.4/0.7, what is the value of (50 cos A + 24 cot A) ?

Given :- tanA = \(\frac{2.4}{0.7}\) = \(\frac{P}{B}\)

Using triplet ( 24 , 7 , 25 ) We find that H = 2.5

Now , (50 cos A + 24 cot A) 

= (50× \(\frac{B}{H}\) + 24 ×\(\frac{B}{P}\) ) 

= (50× \(\frac{0.7}{2.5}\) + 24 ×\(\frac{0.7}{2.4}\) ) 

= 14 + 7

= 21