Practicing Success
Find the value of 'p' for which p(\(\hat{i}\)+\(\hat{j}\)+ \(\hat{k}\)) is a unit vector- |
±1/√2 ±1/√7 ±1/√3 ±1/√5 |
±1/√3 |
p(\(\hat{i}\)+\(\hat{j}\)+ \(\hat{k}\)) is a unit vector if |p(\(\hat{i}\)+\(\hat{j}\)+ \(\hat{k}\)) |= 1 Now, |p(\(\hat{i}\)+\(\hat{j}\)+ \(\hat{k}\)) |= 1 ⇒ √(p2+p2+p2)= 1 ⇒ √(3p2)= 1 ⇒ √(3)p= 1 ⇒ p= ±1/√3
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