A potential barrier of 0.5 V exists across a p - n junction. If the width of depletion layer is $10^{−6} m$, the intensity of electric field in this region will be:

$1 × 10^6 V/m$ $5 × 10^5 V/m$ $4 × 10^4 V/m$ None of these

$5 × 10^5 V/m$

$E=\frac{V}{d}=\frac{0.5}{10^{-6}}=5 × 10^5 V/m$