If 5sinθ = 12cosθ, then what is the value of secθ ?

5sinθ =  12cos θ

⇒ \(\frac{sin θ}{cos θ}\) = \(\frac{12}{5}\)

⇒ tan θ = \(\frac{12 (P)}{5 (B)}\)

using Pythagoras theorem , 

Hypotenuse = 13

secθ = \(\frac{H}{B}\)= \(\frac{13}{5}\)