A reaction is second order with respect to a reactant. If the concentration of the reactant is increased by 1.5 times, the rate of the reaction
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → Increases by 2.25 times.
For a reaction of order $n$,
$\text{Rate} \propto [A]^n$
Here, the reaction is second order $\rightarrow n = 2$.
Calculation
Let original concentration $= [A]$
New concentration $= 1.5[A]$
$\text{New rate} = k(1.5[A])^2 \text{}$
$= k \times 2.25[A]^2 \text{}$
$= 2.25 \times \text{original rate}$