Angle subtended by a chord AB on the circumference of a circle is 90 degree. If length of chord AB is 16 cm, then what will be radius of this circle ?

8 cm

Let o be the circle's centre and let C is the point on the circumference,

Using if angle subtended by a chord on the circumference of a circle is \({90}^\circ\), then the chord is the circle's diameter.

So, AB is the diameter.

The radius is half of the diameter.

AB = 2(OA) = 2(OB)

⇒ (OA) = (OB) = \(\frac{AB}{2}\) = \(\frac{16}{2}\)

⇒ 8 cm.