Practicing Success
The total electric flux, leaving spherical surface of radius 1 cm, and surrounding an electric dipole is |
$\frac{q}{ε_0}$ Zero $\frac{2q}{ε_0}$ $8πr^2\frac{q}{ε_0}$ |
Zero |
Electric flux passes as due to +q charge of dipole = $\frac{+q}{4 p e_0}$ Electric flux passes due to – q charge of dipole = $-\frac{q}{4 p e_0}$ Net flux passes due to both the charges = $\frac{q}{4 p e_0}-\frac{q}{4 p e_0}$ = 0 |