A car of mass 1000 kg negotiates a banked curve of radius 90m on a frictionless road. If the banking angle is 45°, the speed of the car is :
Answer & explanation
Correct answer: option 4
v = \(\sqrt{Rg tan \theta}\)
v = \(\sqrt{(90)(10)(tan45^0)}\)
v = \(\sqrt{900}\) = 30 m/s