CUET Preparation Today
$\int\limits_0^{\pi / 2} \frac{d x}{a^2 \cos ^2 x+b^2 \sin ^2 x}=$ |
$\frac{\pi}{a b}$ $\frac{\pi}{2 a b}$ $\pi a b$ $\pi^2 a b$ |
$\frac{\pi}{2 a b}$ |
Divide Num. and Den. by cos2x and put tan x = t etc. Hence (2) is the correct answer. |
