If A is a matrix of order $m×n$ and B is a matrix such that AB' such that B'A are defined, the order of matrix B is : |
$n×n$ $n×m$ $m×n$ $m×m$ |
$m×n$ |
The correct answer is Option (3) → $m×n$ Let $B = B_{p×q}⇒B'=B'_{q×p}$ $A=A_{m×n}$ if $AB'$ is defined then $n=q$ So $B'A$ is defined then $p=m$ So order of B is $m×n$ |