Practicing Success
In young’s double slit experiment. Assume intensity of each source is I0 and K1 is equal to difference of maximum and minimum intensity. Now intensity of one source is made $\frac{I_0}{4}$ and K2 is again difference of maximum and minimum intensity. Then $\frac{K_1}{K_2} = $ |
4 3 $\frac{3}{4}$ 2 |
2 |
$\mathrm{K}_1=4 \mathrm{I}_0-0$ In second case $\mathrm{I}_{\max }=\mathrm{I}_0\left(\frac{1}{2}+1\right)^2=\frac{9}{4} \mathrm{I}_0 ; \mathrm{I}_{\min }=\mathrm{I}_0\left(1-\frac{1}{2}\right)^2=\frac{\mathrm{I}_0}{4}$ $\mathrm{~K}_2=\frac{9 \mathrm{I}_0}{4}-\frac{\mathrm{I}_0}{4}=2 \mathrm{I}_0 ; \frac{\mathrm{K}_1}{\mathrm{~K}_2}=2$ |