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The degree of dissociation ($α$) of a weak electrolyte $A_xB_y$ is related to van't Hoff factor (i) by the expression: |
$α = (i-1)/(x + y -1)$ $α = (i-1)/(x + y +1)$ $α = (x + y-1)/(i-1)$ $α = (x + y +1)/(i-1)$ |
$α = (i-1)/(x + y -1)$ |
The correct answer is Option (2) → $α = (i-1)/(x + y -1)$ |
