Practicing Success
Practicing Success
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If \(\frac{8x}{2x^2 + 7x - 2}\) = 1, where x > 0, then find x2 + \(\frac{1}{x^2}\). |
\(\frac{1}{4}\) \(\frac{4}{5}\) \(\frac{2}{5}\) \(\frac{9}{4}\) |
\(\frac{9}{4}\) |
8x = 2x2 + 7x - 2 2x2 - x - 2 = 0 2x (x - \(\frac{1}{2}\) - \(\frac{1}{x}\)) = 0 x - \(\frac{1}{x}\) = \(\frac{1}{2}\) x2 + \(\frac{1}{x^2}\) = (\(\frac{1}{2}\))2 + 2 = \(\frac{9}{4}\) |
