A random variable has the following probability distribution
| $X=x_i$ | 2 | 3 | 4 | 5 |
| $P(X=x_i)$ | 4k | k | 5k | 2k |
The value of P(X < 3) is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{1}{3}$
From the given table
we know that $∑pi=1$
so $4k+k+6k+2k=1$
$12k=1⇒k=\frac{1}{12}$
so $P(X < 3)=4k=\frac{1}{3}$