Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Probability

Question:

The probability distribution of a random variable X is given by

X

0

1

2

3

4

 P(X) 

 0.1 

 k 

 2k 

 2k 

 k 

The value of k is:

Options:

0

0.1

1

$\frac{3}{20}$

Correct Answer:

$\frac{3}{20}$

Explanation:

The correct answer is Option (4) → $\frac{3}{20}$