Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

The  value of $cot^{-1}(-1)+cosec^{-1}(-\sqrt{2}) + sec^{-1} (2)$ , is

Options:

$\frac{5\pi}{6}$

$\frac{2\pi}{3}$

$\frac{7\pi}{6}$

$\frac{\pi}{6}$

Correct Answer:

$\frac{5\pi}{6}$

Explanation:

$cot^{-1}(-1)+cosec^{-1}(-\sqrt{2}) + sec^{-1} (2)$

$=\frac{3\pi}{4}-\frac{\pi}{4}+\frac{\pi}{3}=\frac{5\pi}{6}$