CUET Preparation Today
The range of the function $f(x)=x^2+\frac{1}{x^2+1}$ is |
$[1, \infty)$ $[2, \infty)$ $\left.\frac{3}{2}, \infty\right)$ None of these |
$[1, \infty)$ |
$f(x)=x^2+\frac{1}{1+x^2}$ as $x=0$ $f(x)=1$ $x > 0$ or $x < 0 ⇒ x^2 > 0 ⇒ f(x) > 1$ so $f(x) ≥ 1$ |
