If $\frac{|x|-1}{|x|-2} ≤0$, then x lies in the interval
Answer & explanation
Correct answer: option 3
$\frac{|x|-1}{|x|-2} ≤0$
Using wavy curve method
so
$⇒|x|∈[1,2)⇒x∈(-2, -1] ∪ [1, 2)$
If $\frac{|x|-1}{|x|-2} ≤0$, then x lies in the interval
Correct answer: option 3
$\frac{|x|-1}{|x|-2} ≤0$
Using wavy curve method
so
$⇒|x|∈[1,2)⇒x∈(-2, -1] ∪ [1, 2)$