Practicing Success
Practicing Success
CUET Preparation Today
A discrete random variable X can take values 0, 1, 2, 3. Given that P(X = 0) = P(X = 2) = k and P(X = 1) = P(X = 3) such that E(X2) = 2E(X). The value of k is: |
$\frac{3}{4}$ $\frac{3}{8}$ $\frac{1}{2}$ $\frac{3}{2}$ |
$\frac{1}{2}$ |
The correct answer is Option (3) → $\frac{1}{2}$ |
