If $A = \begin{bmatrix} 2 & 3 \\ 5 & -2 \end{bmatrix}$ be such that $A^{-1} = kA$, then $k$ is equal to
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{1}{19}$ ##
$A^{-1} = kA$
$\frac{1}{-19} \begin{bmatrix} -2 & -3 \\ -5 & 2 \end{bmatrix} = k \begin{bmatrix} 2 & 3 \\ 5 & -2 \end{bmatrix}$
$∴ k = \frac{1}{19}$