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If $A = \begin{bmatrix} 2 & 3 \\ 5 & -2 \end{bmatrix}$ be such that $A^{-1} = kA$, then $k$ is equal to |
19 $\frac{1}{19}$ $-\frac{1}{19}$ $-19$ |
$\frac{1}{19}$ |
The correct answer is Option (2) → $\frac{1}{19}$ ## $A^{-1} = kA$ $\frac{1}{-19} \begin{bmatrix} -2 & -3 \\ -5 & 2 \end{bmatrix} = k \begin{bmatrix} 2 & 3 \\ 5 & -2 \end{bmatrix}$ $∴ k = \frac{1}{19}$ |
