Three capacitors each of capacitance 9 pF are connected in series. The capacitance of the combination would be:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 3 pF
For capacitors in series, the reciprocals of the capacitances add.
\( \displaystyle \frac{1}{C} = \frac{1}{9} + \frac{1}{9} + \frac{1}{9} = \frac{3}{9} \)
\( \displaystyle C = 3\,\mathrm{pF} \)
For \( n \) identical capacitors in series the result is \( C/n \), here \( 9/3 = 3\,\mathrm{pF} \).
Note: This question is from NCERT (2026-27). NTA sets numerical questions from NCERT too, so do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
