Which is not true for the major Product of the reaction?

will react with \(O_3/H_2O-Zn\) dust

The correct answer is option 4. will react with \(O_3/H_2O-Zn\) dust.

The given reaction will proceed via Markonikov's rule.

It is clear from the above reaction that the major product is two optical isomers. So, option 1. Is an optical isomer, is correct.

Since the major product is a secondary alcohol, so, on reaction with Lucas reagent it will give white turbidity after 5 min.

So option 2. Gives white turbidity with Lucas reagent after 5 min, is correct.

The major product formed here is 4-Methylhexan-3-ol which dehydrates easily to give 4-Methylhex-2-ene.

So, option 3. It dehydrates easily, is correct.

In option 4 the reagent given is for ozonolysis reaction, but only alkenes and alkynes are capable of ozonolysis. So, option 4. will react with \(O_3/H_2O-Zn\) dust, is incorrect