CUET Preparation Today
Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(I), (B)-(III), (C)-(II), (D)-(IV) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(A)-(I), (B)-(III), (C)-(II), (D)-(IV) |
The correct answer is Option (2) → (A)-(I), (B)-(III), (C)-(II), (D)-(IV)
(A) Oxalic acid → (I) Ethanedioic acid (HOOC-COOH; simplest dicarboxylic acid with two carbons → ethane + di + oic acid). (B) Adipic acid → (III) Hexanedioic acid (HOOC-(CH₂)₄-COOH; six carbons in chain → hexane + di + oic acid). (C) Lactic acid → (II) Alpha hydroxy propanoic acid (CH₃-CH(OH)-COOH; propanoic acid with -OH at alpha (position 2) carbon). (D) Phthalic acid → (IV) Benzene-1,2-dicarboxylic acid (Benzene ring with two -COOH groups at adjacent (ortho/1,2) positions). |
