Consider the function $f(x)=x^3-3x$. Then Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(II), (B)-(I), (C)-(III), (D)-(IV) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) (A)-(IV), (B)-(III), (C)-(I), (D)-(II) |
(A)-(II), (B)-(I), (C)-(III), (D)-(IV) |
The correct answer is Option (1) → (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
Given $f(x)=x^3-3x$ $f'(x)=3x^2-3=3(x^2-1)$ Critical points from $f'(x)=0$ $x^2-1=0$ $x=1,-1$ $f''(x)=6x$ $f''(-1)=-6<0$ so $x=-1$ is point of local maxima $f''(1)=6>0$ so $x=1$ is point of local minima Local maximum value $f(-1)=(-1)^3-3(-1)=-1+3=2$ Local minimum value $f(1)=1-3=-2$ Correct matching: A-II, B-I, C-III, D-IV. |