CUET Preparation Today
If $y=\log \left(\frac{x^5}{e^5}\right)$, then $\frac{d^2 y}{dx^2}$ is, |
$\frac{-5}{x^2}$ $\frac{-20}{x^4}$ $\frac{x^3}{e^2}$ $\frac{-20 x^3}{e^2}$ |
$\frac{-5}{x^2}$ |
The correct answer is Option (1) - $\frac{-5}{x^2}$ $y = \log\left(\frac{x^5}{e^5}\right)$ $= \log x^5 - \log e^5$ $= 5\log x - 5$ $\frac{dy}{dx} = \frac{5}{x}$ $\frac{d^2 y}{dx^2} = -\frac{5}{x^2}$ $\frac{d^2 y}{dx^2} = -\frac{5}{x^2}$ |
