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The wavelength of emitted wave due to energy transition in hydrogen atom from n = 3 to n = 2 energy level will be |
7840 Å 5362 Å 7219 Å 6563 Å |
6563 Å |
The correct answer is Option (4) → 6563 Å Using Rydberg formula, $\frac{1}{λ}=R_H\left(\frac{1}{{n_i}^2}-\frac{1}{{n_f}^2}\right)$ $⇒\frac{1}{λ}=1.097×10^7\left(\frac{1}{2^2}-\frac{1}{3^2}\right)$ $⇒λ=6563 Å$ |
