The shortest wavelength in the Lyman series of hydrogen spectrum is 912 Å. The shortest wavelength present in Paschen series of spectral lines will be:

8208 Å

The correct answer is Option (1) → 8208 Å

From Rydberg formula

1/λ = R (1/n₁² − 1/n₂²)

For the shortest wavelength, n₂ → ∞.

For Lyman series (n₁ = 1)

1/λᴸ = R

Given

λᴸ = 912 Å

Thus

1/R = 912 Å

For Paschen series (n₁ = 3)

1/λᴾ = R/9

Therefore

λᴾ = 9/R

λᴾ = 9 × 912

λᴾ = 8208 Å