If A is a square matrix such that $A^2 = A$ then which of the following statements are TRUE? (Where I is an identity matrix of same order as A) (A) $(I+A)^4 = I + 15A$ Choose the correct answer from the options given below: |
(A) and (B) only (A), (B) and (C) only (A), (C) and (D) only (A), (B) and (D) only |
(A), (B) and (D) only |
The correct answer is Option (4) → (A), (B) and (D) only ** Given condition: $A^2 = A$. For any power $k \ge 1$, $A^k = A$. Expand $(I + A)^n$ without using any binomial symbols: $(I + A)^n = I + (\text{sum of all coefficients of }A \text{ in expansion})\cdot A$. The total of all coefficients of $A$ (except the first $I$ term) in expansion of $(I + A)^n$ is: $2^n - 1$. Therefore: $(I + A)^n = I + (2^n - 1)\,A$. Now check options: (A) $(I + A)^4 = I + (2^4 - 1)A = I + 15A$ ✔ (B) $(I + A)^2 = I + (2^2 - 1)A = I + 3A$ ✔ (C) $(I + A)^6 = I + (2^6 - 1)A = I + 63A$, not $30A$ ✘ (D) $(I + A)^3 = I + (2^3 - 1)A = I + 7A$ ✔ Correct statements: (A), (B), (D) |