If the seventh day of a month is three days earlier than a Friday, what day will be the nineteenth day of the same month?

Sunday

The correct answer is Option (4) → Sunday

Step 1: Find the 7th day

The problem states that the 7th day is "three days earlier than a Friday."

• 1 day earlier than Friday is Thursday.
• 2 days earlier than Friday is Wednesday.
• 3 days earlier than Friday is Tuesday.

So, the 7th day is a Tuesday.

Step 2: Find the 19th day

Since the 7th is a Tuesday, we can add weeks (7 days) to find subsequent Tuesdays:

• 7th = Tuesday
• 14th (7 + 7) = Tuesday

Now, we count forward from the 14th to the 19th:

• 15th = Wednesday
• 16th = Thursday
• 17th = Friday
• 18th = Saturday
• 19th = Sunday

Alternatively, the difference between the days is $19 - 7 = 12$ days.

$12 \text{ days} = 1 \text{ week and } 5 \text{ odd days}$.

Tuesday + 5 days = Sunday.